Question

A cooler contains 5 cans of soda, 2 colas 2 orange and 1 cherry. Two cans are selected at random without replacement. Find the prob that at least one can is orange

Answer 1

so 5/7 is the answer.
Click "Best answer" if it helped. ^_^

Answer 2

\[P(1)=\frac{\left(\begin{matrix}2 \\ 1\end{matrix}\right)\left(\begin{matrix}8 \\ 1\end{matrix}\right)}{\left(\begin{matrix}10 \\ 2\end{matrix}\right)}=\frac{16}{45}\]
\[P(2)=\frac{\left(\begin{matrix}2 \\ 2\end{matrix}\right)\left(\begin{matrix}8 \\ 0\end{matrix}\right)}{\left(\begin{matrix}10 \\ 2\end{matrix}\right)}=\frac{1}{45}\]
Probability of at least 1 can is orange is
\[\frac{16}{45}+\frac{1}{45}=\frac{17}{45}\]