Question

Write a program in C++ that accepts an integer and adds the square of all integers from 1 to the number entered. Make sure to use a loop…

For instance if 4 is entered, your program should compute 1 + 2*2 + 3*3 + 4*4 = 30.

Answer 1

How far have you gotten?

Answer 2

i'm still figuring out which loop to use

Answer 3

Use a for loop to wrap your computations.

Answer 4

Thank you,
int main()
{
int num;
int sum;
int i;
sum = 0;
cout << "Please enter an integer: " << endl;
cin >> num;

for (i = 1; i < num; ++i)
{
sum = sum + i;
cout << i << "+";
}
cout << num << "=" << sum + num << endl;-
return 0;
}
This is what i've got so far. I'm still stuck on computing the squares...

Answer 5

for (i = 1; i <= num; i++) {
sum = sum + i*i;
}

The problem said to add square of all numbers from 1 to the number entered. I would take that to include the number.

Answer 6

hmm when I enter 4, the result comes out to be 34. That means it adds an extra 4 at the end. How do i get rid of that ?

Answer 7

It is because of your last line, cout << num << "=" << sum + num << endl;
You are printing "num" plus "sum" after the loop, if you were to cout << sum << endl; you would have the correct answer output to the screen.

Answer 8

Just to confuse the issue:

while( num > 0 )
{
sum += num * num;
num--;
}