Question

a rectangular fish pond is 7ft longer than it it wide. a wooden 1ft wide is placed around the pound. the area covered by the pond and the walk is 58 sq ft greater than the area covered by the pond alone. what are the dimmensions of the pond?

Answer 1

@hartnn

Answer 2

let length of pond be l and width = w
7ft longer than it it wide ----> l = w+7
got this ?

Answer 3

yes

Answer 4

by placing 1 feet wide wooden, the total length and width increased by 1, right ?
so, total length = l+1
total width = w+7+1 =w+8
got this ?

Answer 5

yes i see

Answer 6

the area covered by the pond and the walk is 58 sq ft greater than the area covered by the pond alone,

area covered by the pond ----> lw = l (w+7)
area covered by the pond and the walk ----> (l+1)(w+8)
can you form an equation using this ?

Answer 7

(l+1)(w+8) is 58 greater than l (w+7)
so, what can be the equation ?

Answer 8

1L-58=9w? what do i do

Answer 9

how did you get that ?
it'll be
(l+1)(w+8) is 58 greater than l (w+7)
so, if you add, 58 to l(w+7) they both will be equal,
so,
l(w+7) +58 = (l+1)(w+8)
got this ?

Answer 10

now just put there, l=w+7
and you get equation only in 'w'.

Answer 11

50=1L+1w

Answer 12

oh, sorry ,my typing mistake, it'll be

(w+1)(w+8) is 58 greater than w(w+7)
so, if you add, 58 to w(w+7) they both will be equal,
so,
w(w+7) +58 = (w+1)(w+8)
now this is already in 'w'
and the good thing is w^2 gets cancelled from both sides...

Answer 13

w(w+7) +58 = (w+1)(w+8)
w^2+7w+58 = w^2 +9w +8
7w+58 = 9w +8
isn't this easy to solve....

Answer 14

25

Answer 15

w= 25 is correct :)
so. l=..?

Answer 16

so whats the original cordinates

Answer 17

l = w+7 =... ?

Answer 18

32

Answer 19

yes,
so whats the original cordinates

Answer 20

32

Answer 21

means length = 32, width = 25

Answer 22

these are the dimentions of the pond.

Answer 23

57

Answer 24

don't add, dimensions are length X width = 32 X 25

Answer 25

thank you

Answer 26

welcome ^_^