how many numbers between 8 and 195 are divisible by 6? what is their sum?
who can help?
sambhav can u help me pls????
with the use of arithmetic progression
pls help me... im confused about this
the answer is 810
do u want the explanation ???
yes sir... can u pls im thanking u in advance
first digit is 12 last digit divisible by 6 within 195 is 192 so the difference is 6 using formula find out the no. of digit\[n= \frac{ l-a }{ d} +1=\frac{ 192-12 }{ 6 } +1 =31\]
then using the summation formula sum\[=\frac{ n }{ 2 }\left( 2a+\left( n-1 \right) d\right)\] \[\frac{ 31}{ 2 }(24+(14)6) =3348\] iand apolologies for my wrong answer idid it in a hurry
is this wrong sir?
thisone is write i gasve u step by step answer and the firast one which i said'810" was wrong i again apologies for that
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