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you can use the identity : \(\large \sin^2 \theta+\cos^2 \theta =1\)
remember that sin theta is positive in 2nd quadrant ....
how do i identify what sin^2 θ is?
you have cos theta, right ? calculate cos^2 theta =... ? then using that formula i gave find sin^2 theta=...?
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what u get ?
144/169...?
that is cos^2 theta and is correct :) now what about sin^2 theta , using that formula ? could u find ?
did u get the answer ?
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