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OpenStudy (anonymous):
Solve AB=BC for A assuming A,B,C are square matrices and B is invertible. So, I started by multiplying each side on the right by B inverse. giving: AI=BCB^-1 so A=BCB^-1
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OpenStudy (anonymous):
Which is in terms of A, but I am not sure if that is correct, or if there is more simplifying to be done.
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