Question

Please help me find the (k+1) statement for:
2 + 4 + 8 + . . . + 2n = 2(n+1) – 2

I already did the 1 and k statements.
They are(I think):
P1
2(1+1)-2
2(2)-2
4-2=2
P1 = 1 = 2

Pk
Pk = 2 + 4 + 8 + … + 2k = 2(k+1) – 2

Answer 1

@satellite73

Answer 2

@jim_thompson5910

Answer 3

Please Help!

Answer 4

Pk : 2 + 4 + 8 + … + 2k = 2(k+1) – 2

P(k+1) : 2 + 4 + 8 + … + 2k + 2(k + 1)= 2((k+1)+1) – 2

does that help?

Answer 5

Thanks!