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Find the arithmetic mean a_n of the given terms. a_(n-1)=-2x, a_(n+1)=2x
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arithmetic mean is just the average, so, add them and divide it by 2, \(\large a_n = \dfrac{a_{n-1}+a_{n+1}}{2}\)
Oh so like...\[\frac{ -2x+2x }{ 2 }\] But it would equal 0 then
thats your arithmetic mean!
and is correct :)
Ohh so 0 is the answer? Okay thank you! I made it harder than it was
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welcome ^_^
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