Given 3x^2-15x+ (-5) at which point will the curve have slope
(a) 0
(b) 2
(c) - 2

All the answers MUST be points.
(a) The point where the slope is 0 is .
(b) The point where the slope is 2 is .
(c) The point where the slope is - 2 is .

Question

Given 3x^2-15x+ (-5)  at which point will the curve have slope 
(a) 0 
(b) 2 
(c) - 2 

All the answers MUST be points. 
(a) The point where the slope is 0 is . 
(b) The point where the slope is 2 is . 
(c) The point where the slope is - 2 is .

anonymous · Answer

is this calculus? i guess take derivative=slope

anonymous · Answer

a) d/dx(3x^2-15x-5)=0
b) d/dx(3x^2-15x-5)=2
c) d/dx(3x^2-15x-5)=-2

anonymous · Answer

then for each case you will get a value of x which you can plug into original eqn to get the y