Solve.

e^2x+e^x-6=0

a. 0.69
b. 0.69, 1.10
c. 1.10, 0.14
d. 0.14

Question

Solve.

e^2x+e^x-6=0

a. 0.69
b. 0.69, 1.10
c. 1.10, 0.14
d. 0.14

anonymous · Answer

SEX????

anonymous · Answer

@DarkgasherBeyblade What????

anonymous · Answer

Hey... do this... substitute e^x = t... 
You will get a quadratic equation in 't'...
t^2 + t-6 = 0

anonymous · Answer

Ok, well I got the whole -3 and 2 answer but I dont know what to after that

anonymous · Answer

@saloniiigupta95

anonymous · Answer

All fine... now do this...
e^x =-3 ==> x= ?  
e^x = 2 ==> x= ?

anonymous · Answer

Taking much time... hint: log for negative numbers is undefined...

anonymous · Answer

Lol so -3 is no solution? But how do I find the answer for 2?

anonymous · Answer

you will have to use log tables for that... You can definitely reject 'b' and 'c' between :-)
 Hope you know... 
|dw:1362160508662:dw|
Use that to convert it into base 10 form... and log 2 (to the base 10) = 0.3011 approx.