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PreCalc & Trig Help! Picture below. I did one like this already, but for some reason I just can't figure this one out. :/
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B
can you tell me how you found that so i know for the rest of the ones like it ?
let x= o-->sin(o) =0 and 2x=0 ---> sin2x =0 . you can conclude that sinx = sin2x when x =0. other solutions are not right because there are some pairs not satisfy sinx =sin2x.
Okay, thank you.
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for example: in A)if x =pi/2---> sin(pi,2) = 1 but sin 2(pi/2) = sinpi=0
ok, I'm glad you understand
yup thanks!
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