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A' and ' B ' can do a piece of work in 25 days and 30 days respectively. Both start the work together but ' A' leaves the work 8 days before its completion. Find the time in which the work is finished.
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1/25+1/30=a+b 's one days work (1-11/150)=(x-8)
A does 1/25 of the work in 1 day B does 1/30 of the work in 1 day together, in 1 day they do 1/25 + 1/30 of the work Let they both work together for x days then, they'll do x/25 + x/30 of the job after that, B does rest of the job alone for next 8 days => 8/30 of the work hence x/25 + x/30 = 1 -(8/30) = 22/30 solve for "x+8" . Hope it helps?
10 days.
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