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Find the perimeter of a rectangular object which has a length of√(180) feet and a width of √(125) feet
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where in my house or school could i find an object that is 22√5 ft?
perimeter of rectangular object = 2(length+breadth) so \[2(\sqrt{180}+\sqrt{125}) \] \[2(6\sqrt{5}+5\sqrt{5})= 2*11\sqrt{5}\]\[Ans = 22\sqrt{5}\]
you should multiply both the length and the width by two (2) to and add them up to get your answer. hope this helps!
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