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Geometry question on Angles and Perimeter of a Triangle: -Use the figure below (attached as answer) and the given information to calculate the specific angle if angle B = 3x - 1, angle A = 3x - 13, and angle BCD = 136 degrees calculate angle B Please help me, thanks in advance
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here is the diagram
Come up with the equations you know.
BCD = 136 BCD + BCA = 180 B + A + BCA = 180
BCD = 136 and BCD + BCA = 180 Gives us: 136 + BCA = 180 Allowing us to solve for BCA
B = 3x - 1 and A = 3x - 13 and B + A + BCA = 180 Gives us: (3x - 1) + (3x - 13) + BCA = 180 Once we solve for BCA, we can solve for x. Then we plug that into B = 3x - 1 to get B
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That makes sense I'll try that, Thank you
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