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The slope of a function f at any point (x,y) is y/(2x^2). The point (2,1) is on the graph of f. Find the tangent line to the grpah f at x=2.
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You need a function... what is the function?
What is\[ \frac{y}{2x^2} \]supposed to be?
Sorry, didn't type it out word for word my first time around.
Fixed it now.
First find the slope: \[ f(x,y) = y/(2x^2) \\ m =f(2,1) = ? \\ \]Here is the equation for a tangent line at \((x_0,y_0)\) with slope \(m\)\[ y-y_0=m(x-x_0) \]
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