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Mathematics 16 Online
OpenStudy (anonymous):

Find the value of tan(sin^-1(1/2))

OpenStudy (anonymous):

the answer is sqr rt3/3

OpenStudy (anonymous):

How do I find it?

OpenStudy (anonymous):

first calculate sin-1(1/2) which is 30 degree of pi/6 then tan(pi/6) which is 1/sqrt3 = .577

OpenStudy (anonymous):

hope this solves ur problem.

OpenStudy (anonymous):

Thank you c:

OpenStudy (anonymous):

How do I get that over 3 though?

OpenStudy (anonymous):

i am not understanding ur question?

OpenStudy (anonymous):

The final answer is sqr rt3/3

OpenStudy (anonymous):

I just don't know how to get that

OpenStudy (anonymous):

no this cant be the final answer of that question

OpenStudy (anonymous):

Tis' the final answer to this problem good sir u_u

OpenStudy (anonymous):

OpenStudy (anonymous):

but dear sqrt3/3 is 1/sqrt3 in 1/sqrt3 if we multiply by sqrt3 both numerator and denominator it is rt3/3. hope u understand

OpenStudy (anonymous):

I do not my love u_u

OpenStudy (anonymous):

haha hope you know I'm joking cx

OpenStudy (anonymous):

hmmm..i know...so where do u studying and in which class ?

OpenStudy (anonymous):

Homeschooled, and trig and pre calc

OpenStudy (anonymous):

which city??

OpenStudy (anonymous):

Pshh I ain's sayin, you crey cx

OpenStudy (anonymous):

okk dnt sAY...............nyc talking to u, NAmaste... i m from India

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