Mathematics
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OpenStudy (anonymous):
Find the value of tan(sin^-1(1/2))
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OpenStudy (anonymous):
the answer is sqr rt3/3
OpenStudy (anonymous):
How do I find it?
OpenStudy (anonymous):
first calculate sin-1(1/2) which is 30 degree of pi/6
then tan(pi/6) which is 1/sqrt3 = .577
OpenStudy (anonymous):
hope this solves ur problem.
OpenStudy (anonymous):
Thank you c:
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OpenStudy (anonymous):
How do I get that over 3 though?
OpenStudy (anonymous):
i am not understanding ur question?
OpenStudy (anonymous):
The final answer is sqr rt3/3
OpenStudy (anonymous):
I just don't know how to get that
OpenStudy (anonymous):
no this cant be the final answer of that question
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OpenStudy (anonymous):
Tis' the final answer to this problem good sir u_u
OpenStudy (anonymous):
OpenStudy (anonymous):
but dear sqrt3/3 is 1/sqrt3
in 1/sqrt3 if we multiply by sqrt3 both numerator and denominator it is rt3/3.
hope u understand
OpenStudy (anonymous):
I do not my love u_u
OpenStudy (anonymous):
haha hope you know I'm joking cx
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OpenStudy (anonymous):
hmmm..i know...so where do u studying and in which class ?
OpenStudy (anonymous):
Homeschooled, and trig and pre calc
OpenStudy (anonymous):
which city??
OpenStudy (anonymous):
Pshh I ain's sayin, you crey cx
OpenStudy (anonymous):
okk dnt sAY...............nyc talking to u, NAmaste... i m from India