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Mathematics 18 Online
OpenStudy (anonymous):

x^3+1/x+1 fill in the missing terms in the numerator and use long division to find the quotients.

Directrix (directrix):

Is x^3+1/x+1 the same as [ (x^3 + 1 ) ] divided by [( x + 1 ) ] ?

OpenStudy (anonymous):

i think were suppose add 0x^2 spmewhere and divide like a polynomial but im just confused

Directrix (directrix):

0x^2 = 0 ---------- I asked the question because I was unsure which terms are in the numerator and which are in a denominatior.

OpenStudy (anonymous):

x^3+1 ------ x+1

Directrix (directrix):

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