Question

Factor 15x^2 - 37x + 20

Answer 1

do you know how to generally factor a quadratic ?

Answer 2

I know some methods but I guess I miss this one

Answer 3

for \(ax^2+bx+c\), you need to find 2 numbers with sum = b and product = ac
so, for your question, you need to find 2 numbers with sum =-37 and product = 20*15 = 300

Answer 4

I see now :)

Answer 5

so which 2 numbers u get ?
then split -37x accordingly...

Answer 6

I got -20 and -15 what now?

Answer 7

good!
split -37x as -20x-15x
so, you have \(15x^2-15x-20x+20\)
there's a common factor in 1st 2 terms and a common factor in last 2 terms, can you proceed ?

Answer 8

oh wait, -20 and -15 are incorrect :P

Answer 9

Yea :S

Answer 10

try another pair ?

Answer 11

-12 -25 ?

Answer 12

bingo!
split -37x as -25x-12x
so, you have \(15x^2−25x−12x+20\)
there's a common factor in 1st 2 terms and a common factor in last 2 terms, can you proceed ?

Answer 13

x(x15-25)4(3x + 5)

Answer 14

from first 2 terms factor out 5x

Answer 15

5x(3x - 5) - 4(3x + 20)

Answer 16

-12x+20 = -4 (3x+.....?)

Answer 17

its 5 sorry

Answer 18

+5 or -5 ?

Answer 19

-5

Answer 20

so, now factor 3x-5 from that

Answer 21

What do you mean? I dont understand :SS

Answer 22

5x (3x-5) -4(3x-5)
factor out 3x-5
(3x-5)(5x-4)
i meant this, and you're done

Answer 23

Bonjour! Comment allez vous?

Answer 24

i am fine, do u need any help ? with what ?

Answer 25

You are very good at teaching people

Answer 26

oh, thank you very much :) :D

Answer 27

\[15x^2 - 37x + 20 \]
\[(3 x-5) (5 x-4)\]