Question

Factor 8z^2+6z-9

Answer 1

hey

Answer 2

I am good, can you help me?

Answer 3

What do you mean?

Answer 4

Someone help me please !!!!!!!

Answer 5

do you still need help @Christos ?

Answer 6

\[8z^2+6z-9\]
\[(2 z+3) (4 z-3)\]

Answer 7

8z^(2)+6z-9

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (-72) that add up to b (6).In this problem (3)/(2)*-(3)/(4)=-(9)/(8) (which is (c)/(a)) and (3)/(2)-(3)/(4)=(6)/(8) (which is ((b)/(a)) , so insert (3)/(2) as the right hand term of one factor and -(3)/(4) as the right-hand term of the other factor.
(z+(3)/(2))(z-(3)/(4))

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(2z+3)(4z-3)