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Find the vertex, focus, directrix, and focal width of the parabola. x = 3y2
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ahh, algebra 2
it's been a while since algebra 2, and I don't know how to do this lol
all right , do you know how this look like when you graph it?
uh, not really lol
it must be a while huh?
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well i honestly dont even know how to find a focus or directrix or a focal width lmao
alright you must know how to graph this do you? y=3x^2
yes..
please do that
okay done
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|dw:1362326174637:dw|
yep thats what i got..
this is y=3x^2 we want x=3y^2 so we switch x and y in graph
does that mean it will open to the right
|dw:1362326336289:dw|
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