Question

please show me how to factor:::
2x^2-19x+24

Answer 1

i know the answer is (x-8) (2x-3).........but how exactly would i get that?

Answer 2

2x^2-19x+24
First multiply the coefficient of x^2 and the constant.
That is, the coefficient of x^2 here is 2 nd constant is 24.
2*24=48
Then find two factors of 48 such that their sum is -19 and product is 48.
That is
if the factors are a and b
a+b=-19
a*b=48

Answer 3

yeah but 24 and 2 dont add up to -19 or any of the other multiples i can think of for 48

Answer 4

I think the expression u have given shoul be
2x^2-11x+48 and nt 2x^2-19x+48. plzz chck

Answer 5

no its still 2x^2-19x+24

Answer 6

ya u r right. Am sorry.
Let me list out the factors of 48
1,2,3,4,6,8,12,16,24,48,-1,-2,-3,-4,-6,-8,-12,-16,-24,-48.
Nw chck if u can find those numbers

Answer 7

hw abt -3 and -16

Answer 8

so the answer should be (2x-3) (x-16)..........not what the book gives me which is (x-8) (2x-3)

Answer 9

2x^2-19x+24
=2x^2-16x-3x+24
=2x(x-8)-3(x-8)

Answer 10

After finding the numbers u have to split only the mid term using thm.
Gettng t? @happykiddo

Answer 11

oh i see where your going with this THANK YOU :D

Answer 12

this really helped.

Answer 13

Glad to hear that nd welcome:)

Answer 14

yay i just got two more problems right. i dont think i'll be needing more help : )

Answer 15

Congrats for gettng ur problems rght:)