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Mathematics 16 Online
OpenStudy (lucaz):

step by step of dy/dx e^(x²)

OpenStudy (dumbsearch2):

let u = x^2...............then y = e^ u du/dx = 2x................dy/du = e^u chain rule: dy/dx = dy/du * du/dx y = 2xe^(x^2)

OpenStudy (dumbsearch2):

mark my answer as correct if it helped ^_^

pooja195 (pooja195):

http://answers.yahoo.com/question/index?qid=20071122122811AAlYCna it not helping if u take credit for someones work :(

OpenStudy (dumbsearch2):

thanks for the citation @pooja195

OpenStudy (dumbsearch2):

il cite in the future

OpenStudy (lucaz):

I'm just looking for the answer ¬¬

pooja195 (pooja195):

well this website is to help not answers

OpenStudy (lucaz):

the answer helps..

OpenStudy (dumbsearch2):

Code of Conduct : "Give Help, Not Answers I will encourage and guide those needing help, and not just give them an answer"

pooja195 (pooja195):

so dont look for ansewrs

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