Question

Solve the system of equations below...(Will post with equation maker)

Answer 1

\[y=x ^{2}-3x-8, y=-2x+4\]

Answer 2

\[-2x+4 = x^2-3x-8\]

\[0 = x^2-3x+2x-8-4\]

\[0=x^2-x-12\]

\[0=(x-4)(x+3)\]

\[x = 4, x = -3\]

plug the two back into the y = -2x + 4 to find the y values.

Answer 3

I am so silly, thank you so much. That makes perfect sense.

Answer 4

your welcome