Check my work?

Have I set this integral up right? I feel like the bounds on x are easy, just 0 to 1, and the bounds on y are given by the inequality in the problem. Is this totally offbase? See attached

Question

Check my work?

Have I set this integral up right? I feel like the bounds on x are easy, just 0 to 1, and the bounds on y are given by the inequality in the problem. Is this totally offbase? See attached

anonymous · Answer

attachment

anonymous · Answer

No, it says $y\geq 0$ you put $y\geq 3$ as a limit.

anonymous · Answer

3x+y <= 3 graphs as a triangle, I figured they meant the who thing, not just y was less than 3.

anonymous · Answer

$$
3x+y\leq  3\implies y \leq 3-3x
$$

anonymous · Answer

so then I just rewrote in terms of y, y <= 3-3x

anonymous · Answer

This says nothing about the lower bound.

anonymous · Answer

|dw:1362360882973:dw|

anonymous · Answer

Oooooh I see what you mean, yea, I did write 3 on the integral. 

so it should be: 

|dw:1362360975292:dw|