Question

Find the equation of the circle with center at (3, 2) and through the point (5, 4).

Answer 1

Thank you for helping me

Answer 2

(y-3)^2+(x-2)^2 = radius^2

radius = distance between (3,2) and (5,4)

d = sqrt((y2-y1)^2+(x2-x1)^2)

d = sqrt((4-2)^2+(5-3)^2)

d = sqrt(2^2+2^2)

d =sqrt(4+4)

d = sqrt(8)

(y-3)^2+(x-2)^2 = (sqrt(8))^2

(y-3)^2+(x-2)^2 = 8