Question

log8 (x+1) = log8 (2x-2)

log2 x+log2 (x+4) = 5

log4 (x-2) = 2

Answer 1

e^(-3x+4) =22

ln(e^(-3x+4)) = ln(22)

// ln(e^y) = y

-3x+4 = ln(22)

-3x = ln(22)-4

x = (ln(22)-4)/-3

Answer 2

how many problems is this?

Answer 3

four

Answer 4

....now three.

Answer 5

\[\log_4 (x-2) = 2\iff 4^2=x-2\] solve for \(x\)