Question

sOLVE (2x+5)^3-(2x+1)^3=16

Answer 1

start with
put 2x + 3 = t (say)
so eq becomes
(t+2)^3 - (t - 2)^3 = 16
now solve for t

Answer 2

ok

Answer 3

is this correct

Answer 4

(a+b)^3 = a^3 + b^3 + 3ab(a+b)

Answer 5

(a-b)^3 = a^3 - b^3 - 3ab(a - b)

Answer 6

I am stuck here 12y^2=0

Answer 7

y is t ?

Answer 8

if yes then y = 0 is the solution to the above equation

Answer 9

yup

Answer 10

2x+3 = t = 0
x = -3/2
this should be the answer

Answer 11

yes the answer is S.S = {-3/2} I checked the answers

Answer 12

cool
:)