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Can someone please help me solve for b1: A=(b1+b2/2)h
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it is like the formula of area of trapezium, right ?
yes
well, so we have an equation : A=((b1+b2)/2)h first, multiply by 2 to both sides giving us; 2A = (b1+b2)h then divided by h to both sides : 2A/h = b1 + b2 and the last step, subtracted by b2 to both sides : 2A/h - b2 = b1
Thank You
you're welcome
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