Question

a rectangular garden has dimensions of 22 feet by 18 feet. A gravel path of consistent width is to be built around the garden. How wide can the path be if there is enough gravel for 276 square feet?

Answer 1

The area of the garden is 22 * 18
The area of the garden and the path combined is (x + 22)(x + 18)
The area of the path alone is (x + 22)(x + 18) - 22 * 18
(x + 22)(x + 18) - 22*18 = 276
Solve the quadratic equation above.