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In an npn transistor,current will flow with low resistance during the forward bias. Assuming the collector instead of being reverse biased is forward biased, will there be low resistance current flow, will there be current leaving the collector, will electrons still leave the collector to activate the dc power supply.
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This is a case, when both the junctions Base-emitter and Base-collector are forward biased. This is case of SATURATION. Both the diodes will conduct current. From Base to emitter and from Base to collector. Could you explain the word activate the dc power supply ?
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