Question

x+3x^1/2 -4=0

Answer 1

factor

Answer 2

\[x=3x ^{\frac{ 1 }{ 2 }}-4=0\]

Answer 3

\[x+3\sqrt{x}-4=0\]
\[(\sqrt{x}+4)(\sqrt{x}-1)=0\]

Answer 4

\[x ^{2}+3x ^{\frac{ 1 }{ 2 }}-4=0\]

Answer 5

so \(\sqrt{x}=1\implies x=1\) and \(\sqrt{x}=-4\) has no solution

Answer 6

hi satellite73 help me please

Answer 7

i couldnt just multiply everything by 2 and get \[x ^{2}=3x-16=0\]

Answer 8

sorry i meant \[x ^{2}+3x-16=0\]

Answer 9

let us x^1/2=y
squr.. both side
x= y^2
put them in eq..
y^2+3y-4=y^2+4y-y-4=(y-1)(y-4)
y=1,-4
put y=x^1/2=1,-4
x=+1,-1,and x=+2-2