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Algebra
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−10e^2−2b−6=−66
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\[-10e ^{2-2b}-6=-66\]
I added 6 on both sides, then?
divide by \(-10\)
get \[e^{2-2b}=6\]
I m getting 0.104120, is it right?
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i don't know start with \[e^{2-2b}=6\] \[2-2b=\ln(6)\] \[-2b=\ln(6)+2\] \[b=\frac{\ln(6)+2}{-2}\]
no that 2 will become -2 not +2
bcoz we are taking it to the other side
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