Question

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = -226.

-334
-274
-284
-346

Answer 1

@ghazi

Answer 2

@abb0t

Answer 3

@AccessDenied

Answer 4

a22 = -226
a1 + (22-1)d = -226
solve for d
it is a start

Answer 5

so, u have
26 + 21d = -226
move 26 to right right side :
21d = -226 - 26
21d = - 252
d = -252/21
d = 12

Answer 6

oppss d= -12 i meant

Answer 7

now, to get the value of 31st term :
a31 = a1 + (31-1)d
a31 = 26 + 30(-12)
a31 = 26-360 = ... ?

Answer 8

-334

Answer 9

that's right

Answer 10

awesome can you assist with one more?

Answer 11

post it in the new question, please :)