Question

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. 6x+y^2=16, x=y

Answer 1

Is there a graph or diagram to go along with this?

Answer 2

http://www.webassign.net/waplots/8/5/eebf4a991571a868aa0864b8adc02e.gif

Answer 3

ok... ao you have to sketch

\[x = \frac{-y^2}{6} + \frac{16}{6}\]

which is a left facing symmetric about the x- axis and having a vertex at (8/3, 0) I think

it also has y intercepts at y = 4 and y = -4

so it looks like



all you need to do is draw y = x to find the region