Question

Prove:

Answer 1

Hello @Yaho021 , please post your problem so that we can help you ...

If you have posted this question by fault or you have not anything to ask , then please close this question .

Answer 2

\[e ^{i \pi}+ 1 = 0\]

Answer 3

OK can you tell me that what is \(\large{e^{i \pi}}\) ?

Answer 4

@yaho021 Please reply to my question.

Answer 5

\[e^{inx}=\cos(nx)+i\sin(nx)\]
\[e^{iπ}=\cos(π)+i\sin(π)=-1+0i\]

Answer 6

Oh you disclosed the answer , I thought that the asker will tell it by his/her own.