What is the remainder of (x3 – 6x – 9x + 3) ÷ (x - 3) A. -51 B. -51 x - 3 C. -17 x D. -17 x - 3
use the remainder theorem : if f(x) divided by (x-3), then f(3) as remainder so, what's (x^3 – 6x^2 – 9x + 3) for x=3 ? (sorry, i assumed u have typo it should -6x^2, right ?) it is 3^3 - 6(3)^2 - 9(3) + 3 = .... ?
what i have there is the right one
try this mommy :) 3^3 - 6(3)^2 - 9(3) + 3 = ?
Thank for trying to help but I really do not get any of this
I'm doing this all online and it is very hard to try and break it down and learn how to do all this
well, i will figure out of it 3^3 - 6(3)^2 - 9(3) + 3 = 27 - 6(9) - 27 + 3 = 27 - 54 - 27 + 3 = -54 + 3 = - 51
it is A, mommy :)
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