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English 11 Online
OpenStudy (anonymous):

Can someone help me? I'll redo this in the equation box in just a second. (x-y)3/(y3+z3)÷(x2-2xy+y2)/(y2-yz+z2)

OpenStudy (anonymous):

\[(x-y)^3/(y^3+z^3)÷(x^2-2xy+y^2)/(y^2-yz+z^2)\]

OpenStudy (anonymous):

Can anyone help?

OpenStudy (anonymous):

@Hero?

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

You should be in the math section.

OpenStudy (anonymous):

haha sorry, I wasn't paying attention to that. Thanks.

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