Question

-3x^2+3x+2=0

Answer 1

Two numbers that add to get \(3\) and their product is \(-6\). Tsk tsk

Answer 2

Are you trying to solve for x? If so, you should get 1/6*(3+sqrt(33)) or 1/6*(3-sqrt(33))

Answer 3

Yes im solvin for x but im confused as to how

Answer 4

Try using the quadratic equation.

-3x^2+3 x+2 = 0

a*x^2+b*x+c = 0 |
x | indeterminate variable
a | quadratic coefficient
b | linear coefficient
c | constant coefficient
(x = (-b±sqrt(b^2-4*a*c))/(2*a))

(x = (-3±sqrt(3^2-4(-3)(2))/(2*(-3))

And then solve above.