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Precalculus
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Jim stood on flat ground 42 feet from the base of a tower. He measured the angle of elevation to the top of the tower as 73°40'. How tall is the tower?
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40' = (40/60)° = 0.667° |dw:1362540308422:dw|
use defined of tan tan73.667° = x/42 solve for x
with x is tall of the tower
opppssss.. the sign of right angle is left :) |dw:1362541097118:dw|
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