Ask your own question, for FREE!
Physics 18 Online
OpenStudy (anonymous):

circuits

OpenStudy (anonymous):

|dw:1362546022503:dw|

OpenStudy (anonymous):

Parallel

OpenStudy (anonymous):

\[Q=Q_1=Q_2\] \[V=V_1+V_2\] \[V=\frac Q C\] \[\frac {\cancel Q} C=\frac {\cancel Q}{C_1}+\frac{\cancel Q}C_2\] \[\frac 1 C=\frac 1{C_1}+\frac 1{C_2}\]

OpenStudy (anonymous):

@experimentX It's series isn't it?

OpenStudy (experimentx):

|dw:1362546785888:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!