Question

x-4/x+2<1 because the x-4 is divided by x+2 well times both sides by x+2 so we now have the following (x+2) (x-4)<1(x+2) than we distr (x+2) (x-4) which we get x^2-3<1 did i miss something here plz help

Answer 1

i am here

Answer 2

am I on the right track?

Answer 3

you would normally multiply by the square of the denominator

\[(x + 2)(x -4) < (x + 2)^2\]

because if you multiply by (x + 2)

you have

\[\frac{(x - 4)}{(x + 2)} \times (x + 2) < 1 \times (x + 2)\]

which becomes

\[\frac{(x -4)(x+2)}{(x +2)} < (x +2) \]

cancel the common factor in the fraction leaves

\[(x -4) < (x + 2)\]

hope this helps

Answer 4

where is the 0ne?

Answer 5

well 1 times anything is 1 so 1 times (x + 2) is x + 2