Question

how o u solve (3x^2y)^3

Answer 1

\[(3x^2y)^3=3^3(x^2)^3(y^1)^3\]

Answer 2

Does that help?

Answer 3

What is 3 to the third?

Answer 4

the power of 3 is operating on each part of the expression and can be written in expanded form as

\[3^3 \times (x^2)^3 \times (y^1)^3\]

to simplify the variables use the index law for power of a power which means multiply the powers

\[(x^a)^b = x^{a \times b}\]

Answer 5

thank u guys