Question

A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical components of the force?

Answer 1

using\[\cos(\theta)=F_x/F\] and \[\sin(\theta)=F_y/F\]
where F is the resultant force (73.8 N)

you find the components by:
\[F_x=73.8*\cos(39.0)\]\[F_y=73.8*\sin(39.0)\]