Question

solve elimination plz show work
x+y=20
x-y=4

Answer 1

plz i need help

Answer 2

THERE ARE TWO STEPS !

FIRST STEP:-
In x+y=20,
their should be following cases:

1) x=0 and y=20

2) x=1 and y=19

3) x=2 and y=18

4) x=3 and y=17

5) x=4 and y=16

6) x=5 and y=15

7) x=6 and y=14

8) x=7 and y=13

9) x=8 and y=12

10) x=9 and y=11

11) x=10 and y=10

12) x=11 and y=9

13) x=12 and y=8

14) x=13 and y=7

15) x=14 and y=6

16) x=15 and y=5

17) x=16 and y=4

18) x=17 and y=3

19) x=18 and y=2

20) x=19 and y=1

21) x=20 and y=0



By using above value,

calculate the x-y = 4 .

Then the value which x-y = 4 is the answere.

Thus, x=12 and y=8.



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SECOND STEP:-


It is the very easy step.

Calculate the substraction of the equation x+y = 20 and x-y=4


x + y = 20
-
x - y = 4
--------------------------------
y + y = 16

Therefore,

y + y = 16

=> 2y = 16
=> y = 16/2
=> y=8

The value of y is calculated. So, lets find the value of x
1)
x + y = 20
=> x + 8 = 20
=> x = 20 - 8
=> x = 12

2)
x - y = 4
=> x - 8 = 4
=> x = 4 + 8
=> x = 12

Therefore x=12

Thus x =12 and y = 8.

Answer 3

Add the first equation to the second equation:
x+y
+x-y
--------
2x=24
Since the ys cancel, we have 2x=24. Dividing both sides by two, we obtain x=12. Plugging in x=12 to the original equations:
12-y=4 →y is 8

Answer 4

thanks