Question

Find the slope of the tangent line to the curve y=logBase5(3x-1) at point x=3

Answer 1

it can rewriten as
5^y = 3x-1
take derivative by implicit
5^y ln5 dy = 3 dx
dy/dx = 3/(5^y ln 5)
so, m = 3/(5^y ln 5) = 3/((3x-1)ln5)
now, put the value of x=3
m = 3/(3(3)-1)ln5 = 3/8ln5

Answer 2

Thank you!(:

Answer 3

you'r welcome