Question

Rewrite with only sin x and cos x.

sin 3x - cos x

A. 2 sin x - sin3x - cos x

B. 2 sin x cos2x + sin x - 2 sin3x - cos x

C.2 sin3x cos4x + 1

D. 3 sin x cos x - sin3x - cos x

Answer 1

PLEASE HELP ANYBODY :)

Answer 2

\[\sin(3x)-cosx=\sin(2x+x)-cosx=\sin2xcosx+\cos2xsinx-cosx\]

Answer 3

\[2sinxcosxcosx+(\cos^2x-\sin^2x)sinx -cosx=2sinxcos^2x+\cos^2x-\sin^3x-cosx\]

Answer 4

Is the original problem sin(3x) or sin^3x?

Answer 5

i am not sure,, what i typed is what was given

Answer 6

sin 3x-cos x

Answer 7

It's D

Answer 8

thank you so much! !!!

Answer 9

yw