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solve for x (3/k)=(1/x)-(2/y)
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\[\frac{3}{k}=\frac{1}{x}-\frac{2}{y}\]
Add 2/y to both sides
\[\frac{3}{k}+\frac{2}{y}=\frac{1}{x}\]
Add the two fractions on the left side
\[\frac{3y+2k}{ky}=\frac{1}{x}\]
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Take reciprocals of each side.
\[\frac{ky}{3y+2k}=x\]
thank you very much...can you help me with one more problem?
post it
(5x/2x-3)+4 [add and simplify]
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\[\frac{5x}{2x-3}+4=\frac{5x+4(2x-3)}{2x-3}=\frac{5x+8x-12}{2x-3}=\]
\[\frac{13x-12}{2x-3}\]
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