Question

Can someone help me find the exact value of - sec10* /csc80*

Answer 1

please help me please

Answer 2

do you understand the concept of secant and cosecant first of all?

Answer 3

Yes, there might be some gaps in between but I can get the bigger picture :D

Answer 4

@all

Answer 5

@everyone

Answer 6

hmm how about the unit circle?

Answer 7

No my friend, I donnto do graph just equations and stuff like that :)

Answer 8

I just solve broblems without graph

Answer 9

okay so what is the sine 10* and cosine of 80*

Answer 10

sec (90-y) = csc (y)
put y=80 here, what u get ?

Answer 11

I stil dont understand how
To solve this problem!!!

Answer 12

:O
\(\sin (90-x)=\cos x \\ \cos(90-x)=\sin x\\ \tan (90-x)=\cot x \\ \cot(90-x)=\tan x\\ \sec(90-x)= \csc x \\ \csc(90-x)=\sec x \)
so, using \(\sec(90-x)= \csc x\)
put x= 80 , what u get ??

Answer 13

why is it so difficult to put x=80 in that ?