Mathematics
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OpenStudy (dls):
From a bag,containing 7 red,8 black and 5 white balls..3 balls are drawn at random
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OpenStudy (dls):
Find P of getting
1)1 red 2 white
D)not more than 1 red ball
hartnn (hartnn):
your attempt?
since its not given, we assume that its without replacement
OpenStudy (dls):
tell 2ndpart:/
OpenStudy (shubhamsrg):
2nd part?
pard d) ?
OpenStudy (shubhamsrg):
part*
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OpenStudy (dls):
yes
OpenStudy (shubhamsrg):
not more than 1 red balls means either 0 red balls OR 1 red ball
OpenStudy (dls):
yes
OpenStudy (shubhamsrg):
So where are you stuck of you know that? -_-
OpenStudy (shubhamsrg):
if*
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OpenStudy (dls):
7C0*8C1*5C2/20C3 + 7C1*8C1*5C1/20C3 +8C2*5C1/20C3
OpenStudy (dls):
smt like this?
OpenStudy (shubhamsrg):
ohh! wow! :O
OpenStudy (shubhamsrg):
no!
OpenStudy (dls):
:/
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OpenStudy (shubhamsrg):
for 0 red balls,
7C0 * 13C3 / 20C3
for 1 red ball
7C1 * 13C2 /20C3
OpenStudy (dls):
@hartnn >.<
OpenStudy (shubhamsrg):
@shubhamsrg
OpenStudy (dls):
@DLS help..me:|
OpenStudy (dls):
@hartnn i got it dw :)
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hartnn (hartnn):
@shubhamsrg is correct,
not more than 1 red ball = 0 red +1 red
=7 C0 * 13C3 / 20C3 + 7C1 * 13C2 /20C3
OpenStudy (shubhamsrg):
how did you get it but? :|
OpenStudy (dls):
i wrote sarcastically :P
OpenStudy (dls):
u told on facebook :3
hartnn (hartnn):
not more than 1 red ball =either 0 red 'or' 1 red
or =+
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OpenStudy (shubhamsrg):
Thats what I wanted to hear! B|
OpenStudy (dls):
:P