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Mathematics 19 Online
OpenStudy (dls):

From a bag,containing 7 red,8 black and 5 white balls..3 balls are drawn at random

OpenStudy (dls):

Find P of getting 1)1 red 2 white D)not more than 1 red ball

hartnn (hartnn):

your attempt? since its not given, we assume that its without replacement

OpenStudy (dls):

tell 2ndpart:/

OpenStudy (shubhamsrg):

2nd part? pard d) ?

OpenStudy (shubhamsrg):

part*

OpenStudy (dls):

yes

OpenStudy (shubhamsrg):

not more than 1 red balls means either 0 red balls OR 1 red ball

OpenStudy (dls):

yes

OpenStudy (shubhamsrg):

So where are you stuck of you know that? -_-

OpenStudy (shubhamsrg):

if*

OpenStudy (dls):

7C0*8C1*5C2/20C3 + 7C1*8C1*5C1/20C3 +8C2*5C1/20C3

OpenStudy (dls):

smt like this?

OpenStudy (shubhamsrg):

ohh! wow! :O

OpenStudy (shubhamsrg):

no!

OpenStudy (dls):

:/

OpenStudy (shubhamsrg):

for 0 red balls, 7C0 * 13C3 / 20C3 for 1 red ball 7C1 * 13C2 /20C3

OpenStudy (dls):

@hartnn >.<

OpenStudy (shubhamsrg):

@shubhamsrg

OpenStudy (dls):

@DLS help..me:|

OpenStudy (dls):

@hartnn i got it dw :)

hartnn (hartnn):

@shubhamsrg is correct, not more than 1 red ball = 0 red +1 red =7 C0 * 13C3 / 20C3 + 7C1 * 13C2 /20C3

OpenStudy (shubhamsrg):

how did you get it but? :|

OpenStudy (dls):

i wrote sarcastically :P

OpenStudy (dls):

u told on facebook :3

hartnn (hartnn):

not more than 1 red ball =either 0 red 'or' 1 red or =+

OpenStudy (shubhamsrg):

Thats what I wanted to hear! B|

OpenStudy (dls):

:P

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