Question

I need identities for tan/cot please

Answer 1

\[\frac{\tan}{\cot}=\frac{\tan}{\frac{1}{\tan}}=\tan^2\]

Answer 2

\[\tan(A+B+C )=(\tan A +\tan B + \tan C-tanAtanBtanC)\div(1-tanAtanB-tanBtanC-tanCtanA)\]

Answer 3

which type of identity r u want

Answer 4

\[\frac{1 }{ \tan \theta } = \cot \theta = \frac{ \sin \theta }{ \cos }\]

Answer 5

I know tan and sec and i need cos

Answer 6

cot is 6

Answer 7

http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf